JEOPARDY Final Strategy
A, B, & C
Depending upon the category, there are unique probabilities for each player (e.g., pA; pB; pC).
If A > 2 * B, “game over”.
If 2 * C < A – B, C is moot.
2 * B is B’s MAX score.
A needs to bet .5 of (BMAX – A)
A – ABET is C’s target.
BUT, (there is always a big butt), they should all play to tie. There’s no skin off the leader’s nose in a tie.
Then it’s up to the gods of chance?
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